背景
古人展现了非凡的智慧，孕育了《易经》这一博大精深的经典之作。然而，多数人对《易经》的认知往往局限于其占卜的层面，误以为它仅仅是预测未来的工具。实则，《易经》蕴含了深刻的哲学思想、宇宙观以及道德伦理，是探讨自然法则、人生智慧与社会和谐的宝库。由于缺乏对其全面而系统的学习，我们往往难以窥见其全貌，错过了深入领略这一文化瑰宝精髓的机会。
见解
六十四卦
就比如乾卦，潜龙勿用，阳在下也。见龙在田，德施普也。终日乾乾，反复道也。或跃在渊，进无咎也。飞龙在天，大人造也。亢龙有悔，盈不可久也。可能看不懂具体说了个啥事情，我大致说一下我的见解。
///////////////////////////////////////////////////// 程序名称：卜卦人生// 编译环境：Mictosoft Visual Studio 2022, EasyX_20200315(beta)// 作 者：luoyh <2864292458@qq.com>// 最后修改：2024-8-19// 公 众 号：C语言研究//void DrawYAO(int num, int x, int y); // 绘制爻void ISYD(int NUM);int Nums;void decimalToBinaryIntArray(int decimal, int binaryArray[6]);int generateRandomNumber(int min, int max);const char* yiJingGuaNames[64] ={"坤为地","地雷复","地水师","地泽临","地山谦","地火明夷","地风升","地天泰","雷地豫","震为雷","雷水解","雷泽归妹","雷山小过","雷火丰","雷风恒","雷天大壮","水地比","水雷屯","坎为水","水泽节","水山蹇","水火既济","水风井","水天需","泽地萃","泽雷随","泽水困","兑为泽","泽山咸","泽火革","泽风大过","泽天夬","山地剥","山雷颐","山水蒙","山泽损","艮为山","山火贲","山风蛊","山天大畜","火地晋","火雷噬嗑","火水未济","火泽睽","火山旅","离为火","火风鼎","火天大有","风地观","风雷益","风水涣","风泽中孚","风山渐","风火家人","巽为风","风天小畜","天地否","天雷无妄","天水讼","天泽履","天山遁","天火同人","天风姤","乾为天"};int main(){initgraph(640, 480);setbkcolor(WHITE);cleardevice();srand(time(0));ExMessage msg; // 定义一个鼠标消息BeginBatchDraw();flushmessage();while (true){peekmessage(&msg, EX_MOUSE);FlushBatchDraw();cleardevice();// 鼠标按下，开发摇动if (msg.lbutton){Nums = generateRandomNumber(0, 63);ISYD(Nums);}else{ISYD(Nums);}}return 0;}void ISYD(int NUM){settextcolor(BLACK);settextstyle(50, 0, _T("楷体"));setbkmode(TRANSPARENT);RECT r = { 0,0,640,120 };drawtext(yiJingGuaNames[Nums], &r, DT_CENTER | DT_VCENTER | DT_SINGLELINE);int binaryArray[6]; // 整数数组，但每个元素只存储一个二进制位decimalToBinaryIntArray(NUM, binaryArray);for (int i = 5; i >= 0; i--){DrawYAO(binaryArray[i], 220, 320 - i * 40);}}int generateRandomNumber(int min, int max){// 确保max大于等于minif (max < min){int temp = min;min = max;max = temp;}// 使用rand()生成随机数，并通过取模确保结果在min到max之间int random = rand() % (max - min + 1) + min;return random;}void DrawYAO(int num, int x, int y){setfillcolor(BLACK);if (num == 1){solidrectangle(x, y, x + 200, y + 20); // 二进制为1时，绘制长实线}if (num == 0){solidrectangle(x, y, x + 100 - 10, y + 20); // 二进制为0时，绘制短实线solidrectangle(x + 100 + 10, y, x + 200, y + 20);}}// 将一个十进制数转换为二进制存储到数组中void decimalToBinaryIntArray(int decimal, int binaryArray[6]){for (int i = 0; i < 6; i++){// 从最低位开始填充binaryArray[i] = decimal % 2;decimal /= 2;}}
效果
