CREATE TABLE[StudentScores]
(
[UserName] NVARCHAR(20), --学生姓名
[Subject] NVARCHAR(30), --科目
[Score] FLOAT, --成绩
)
INSERTINTO[StudentScores]SELECT'Nick','语文',80
INSERTINTO[StudentScores]SELECT'Nick','数学',90
INSERTINTO[StudentScores]SELECT'Nick','英语',70
INSERTINTO[StudentScores]SELECT'Nick','生物',85
INSERTINTO[StudentScores]SELECT'Kent','语文',80
INSERTINTO[StudentScores]SELECT'Kent','数学',90
INSERTINTO[StudentScores]SELECT'Kent','英语',70
INSERTINTO[StudentScores]SELECT'Kent','生物',85
(提示:可以左右滑动代码)
SELECT
UserName,
MAX(CASESubjectWHEN'语文'THENScoreELSE0END)AS'语文',
MAX(CASESubjectWHEN'数学'THENScoreELSE0END)AS'数学',
MAX(CASESubjectWHEN'英语'THENScoreELSE0END)AS'英语',
MAX(CASESubjectWHEN'生物'THENScoreELSE0END)AS'生物'
FROMdbo.[StudentScores]
GROUPBYUserName
CREATE TABLE [Inpours]
(
[ID] INT IDENTITY(1,1),
[UserName] NVARCHAR(20), --游戏玩家
[CreateTime] DATETIME, --充值时间
[PayType] NVARCHAR(20), --充值类型
[Money] DECIMAL, --充值金额
[IsSuccess] BIT, --是否成功 1表示成功, 0表示失败
CONSTRAINT [PK_Inpours_ID] PRIMARY KEY(ID)
)
INSERT INTO Inpours SELECT '张三', '2010-05-01', '支付宝', 50, 1
INSERT INTO Inpours SELECT '张三', '2010-06-14', '支付宝', 50, 1
INSERT INTO Inpours SELECT '张三', '2010-06-14', '手机短信', 100, 1
INSERT INTO Inpours SELECT '李四', '2010-06-14', '手机短信', 100, 1
INSERT INTO Inpours SELECT '李四', '2010-07-14', '支付宝', 100, 1
INSERT INTO Inpours SELECT '王五', '2010-07-14', '工商银行卡', 100, 1
INSERT INTO Inpours SELECT '赵六', '2010-07-14', '建设银行卡', 100, 1
SELECT
CONVERT(VARCHAR(10), CreateTime, 120) AS CreateTime,
CASE PayType WHEN '支付宝' THEN SUM(Money) ELSE 0 END AS '支付宝',
CASE PayType WHEN '手机短信' THEN SUM(Money) ELSE 0 END AS '手机短信',
CASE PayType WHEN '工商银行卡' THEN SUM(Money) ELSE 0 END AS '工商银行卡',
CASE PayType WHEN '建设银行卡' THEN SUM(Money) ELSE 0 END AS '建设银行卡'
FROM Inpours
GROUP BY CreateTime, PayType
SELECT
CreateTime,
ISNULL(SUM([支付宝]) , 0) AS [支付宝],
ISNULL(SUM([手机短信]) , 0) AS [手机短信],
ISNULL(SUM([工商银行卡]), 0) AS [工商银行卡],
ISNULL(SUM([建设银行卡]), 0) AS [建设银行卡]
FROM
(
SELECT
CONVERT(VARCHAR(10), CreateTime, 120) AS CreateTime,
CASE PayType WHEN '支付宝' THEN SUM(Money) ELSE 0 END AS '支付宝' ,
CASE PayType WHEN '手机短信' THEN SUM(Money) ELSE 0 END AS '手机短信',
CASE PayType WHEN '工商银行卡' THEN SUM(Money) ELSE 0 END AS '工商银行卡',
CASE PayType WHEN '建设银行卡' THEN SUM(Money) ELSE 0 END AS '建设银行卡'
FROM Inpours
GROUP BY CreateTime, PayType
) T
GROUP BY CreateTime
DECLARE @cmdText VARCHAR(8000);
DECLARE @tmpSql VARCHAR(8000);
SET @cmdText = 'SELECT CONVERT(VARCHAR(10), CreateTime, 120) AS CreateTime,' + CHAR(10);
SELECT @cmdText = @cmdText + ' CASE PayType WHEN ''' +
PayType + ''' THEN SUM(Money) ELSE 0 END AS ''' + PayType
+ ''',' + CHAR(10) FROM (SELECT DISTINCT PayType FROM Inpours ) T
SET @cmdText = LEFT(@cmdText, LEN(@cmdText) -2) --注意这里,如果没有加CHAR(10) 则用LEFT(@cmdText, LEN(@cmdText) -1)
SET @cmdText = @cmdText + ' FROM Inpours
GROUP BY CreateTime, PayType ';
SET @tmpSql ='SELECT CreateTime,' + CHAR(10);
SELECT @tmpSql = @tmpSql + ' ISNULL(SUM(' + PayType + '), 0) AS ''' +
PayType + ''',' + CHAR(10)
FROM (SELECT DISTINCT PayType FROM Inpours ) T
SET @tmpSql = LEFT(@tmpSql, LEN(@tmpSql) -2) + ' FROM (' + CHAR(10);
SET @cmdText = @tmpSql + @cmdText + ') T GROUP BY CreateTime ';
PRINT @cmdText
EXECUTE (@cmdText);
SELECT CreateTime, [支付宝] , [手机短信],[工商银行卡] , [建设银行卡]
FROM
(
SELECT CONVERT(VARCHAR(10), CreateTime, 120) AS CreateTime,PayType, Money
FROM Inpours
) P
PIVOT (
SUM(Money)
FOR PayType IN
([支付宝], [手机短信], [工商银行卡], [建设银行卡])
) AS T
ORDER BY CreateTime
有时可能会出现这样的错误:
消息 325,级别 15,状态 1,第 9 行
‘PIVOT’ 附近有语法错误。您可能需要将当前数据库的兼容级别设置为更高的值,以启用此功能。有关存储过程 sp_dbcmptlevel 的信息,请参见帮助。
这个是因为:对升级到 SQL Server 2005 或更高版本的数据库使用 PIVOT 和 UNPIVOT 时,必须将数据库的兼容级别设置为 90 或更高。有关如何设置数据库兼容级别的信息,请参阅 sp_dbcmptlevel (Transact-SQL)。例如,只需在执行上面脚本前加上 EXEC sp_dbcmptlevel Test, 90; 就OK了, Test 是所在数据库的名称。
下面我们来看看列转行,主要是通过UNION ALL ,MAX来实现。假如有下面这么一个表
Create Table ProgrectDetail
(
ProgrectName NVARCHAR(20), --工程名称
OverseaSupply INT, --海外供应商供给数量
NativeSupply INT, --国内供应商供给数量
SouthSupply INT, --南方供应商供给数量
NorthSupply INT --北方供应商供给数量
)
INSERT INTO ProgrectDetail
SELECT 'A', 100, 200, 50, 50
UNION ALL
SELECT 'B', 200, 300, 150, 150
UNION ALL
SELECT 'C', 159, 400, 20, 320
UNION ALL
SELECT 'D', 250, 30, 15, 15
SELECT ProgrectName, 'OverseaSupply' AS Supplier,
MAX(OverseaSupply) AS 'SupplyNum'
FROM ProgrectDetail
GROUP BY ProgrectName
UNION ALL
SELECT ProgrectName, 'NativeSupply' AS Supplier,
MAX(NativeSupply) AS 'SupplyNum'
FROM ProgrectDetail
GROUP BY ProgrectName
UNION ALL
SELECT ProgrectName, 'SouthSupply' AS Supplier,
MAX(SouthSupply) AS 'SupplyNum'
FROM ProgrectDetail
GROUP BY ProgrectName
UNION ALL
SELECT ProgrectName, 'NorthSupply' AS Supplier,
MAX(NorthSupply) AS 'SupplyNum'
FROM ProgrectDetail
GROUP BY ProgrectName
用UNPIVOT 实现如下:
SELECT ProgrectName,Supplier,SupplyNum
FROM
(
SELECT ProgrectName, OverseaSupply, NativeSupply,
SouthSupply, NorthSupply
FROM ProgrectDetail
)T
UNPIVOT
(
SupplyNum FOR Supplier IN
(OverseaSupply, NativeSupply, SouthSupply, NorthSupply )
) P
推荐一下我的小报童《SQL145题》, 集合了145道日常工作中遇到的面试题和笔试题, 所有题目均通过测试,目前买断价仅需10元, 分享他人购买还可挣5元佣金, 长按下方二维码即可订阅。