类介绍
public class BigDecimal extends Number implements Comparable<BigDecimal> {
// 该BigDecimal的未缩放值
private final BigInteger intVal;
// 精度,可以理解成小数点后的位数
private final int scale;
// BigDecimal中的十进制位数,如果位数未知,则为0(备用信息)
private transient int precision;
// Used to store the canonical string representation, if computed.
// 这个我理解就是存实际的BigDecimal值
private transient String stringCache;
// 扩大成long型数值后的值
private final transient long intCompact;
}
从例子入手
@Test
public void testBigDecimal() {
BigDecimal bigDecimal1 = BigDecimal.valueOf(2.36);
BigDecimal bigDecimal2 = BigDecimal.valueOf(3.5);
BigDecimal resDecimal = bigDecimal1.add(bigDecimal2);
System.out.println(resDecimal);
}
/**
* Returns a BigDecimal whose value is (this + augend),
* and whose scale is max(this.scale(), augend.scale()).
*/
public BigDecimal add(BigDecimal augend) {
if (this.intCompact != INFLATED) {
if ((augend.intCompact != INFLATED)) {
return add(this.intCompact, this.scale, augend.intCompact, augend.scale);
} else {
return add(this.intCompact, this.scale, augend.intVal, augend.scale);
}
} else {
if ((augend.intCompact != INFLATED)) {
return add(augend.intCompact, augend.scale, this.intVal, this.scale);
} else {
return add(this.intVal, this.scale, augend.intVal, augend.scale);
}
}
}
private static BigDecimal add(final long xs, int scale1, final long ys, int scale2) {
long sdiff = (long) scale1 - scale2;
if (sdiff == 0) {
return add(xs, ys, scale1);
} else if (sdiff < 0) {
int raise = checkScale(xs,-sdiff);
long scaledX = longMultiplyPowerTen(xs, raise);
if (scaledX != INFLATED) {
return add(scaledX, ys, scale2);
} else {
BigInteger bigsum = bigMultiplyPowerTen(xs,raise).add(ys);
return ((xs^ys)>=0) ? // same sign test
new BigDecimal(bigsum, INFLATED, scale2, 0)
: valueOf(bigsum, scale2, 0);
}
} else {
int raise = checkScale(ys,sdiff);
long scaledY = longMultiplyPowerTen(ys, raise);
if (scaledY != INFLATED) {
return add(xs, scaledY, scale1);
} else {
BigInteger bigsum = bigMultiplyPowerTen(ys,raise).add(xs);
return ((xs^ys)>=0) ?
new BigDecimal(bigsum, INFLATED, scale1, 0)
: valueOf(bigsum, scale1, 0);
}
}
}
首先17行校验了一下数值范围 18行将ys扩大了10的n次倍,这里n=raise=1,所以返回的scaledY=350 接着就进入到20行的add方法:
private static BigDecimal add(long xs, long ys, int scale){
long sum = add(xs, ys);
if (sum!=INFLATED)
return BigDecimal.valueOf(sum, scale);
return new BigDecimal(BigInteger.valueOf(xs).add(ys), scale);
}
结论
链接:https://juejin.cn/post/7348709938023940136
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